Input a sentence and find the length of each word of that sentence.
#include <stdio.h>
#include <conio.h>
#include <string.h>
void main ( )
{
char nm1[80], nm2[80][80];
int i = 0, j = 0, c = 0, y = 0, ln;
clrscr ( );
printf("\n\n\n\t Enter a sentence....:"); gets(nm1);
ln = strlen (nm1);
for ( y = 0; y <= ln; y++ )
{
if ( nm1[y] != ' ' && nm1[y] != '\0' )
{
nm2[i][ j] = nm1[y];
j++;
}
else
{
nm2[i][ j] = '\0';
i++;
j = 0;
}
}
printf("\n\n\n\t\t WORD \t LENGTH OF WORD \n\t\t________________________");
for ( c = 0; c < i; c++ )
{
printf("\n\n\n\t\t %s \t\t %d", nm2[c], strlen (nm2[c]) );
}
getch ( );
}
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#include <stdio.h>
#include <conio.h>
#include <string.h>
void main ( )
{
char nm1[80], nm2[80][80];
int i = 0, j = 0, c = 0, y = 0, ln;
clrscr ( );
printf("\n\n\n\t Enter a sentence....:"); gets(nm1);
ln = strlen (nm1);
for ( y = 0; y <= ln; y++ )
{
if ( nm1[y] != ' ' && nm1[y] != '\0' )
{
nm2[i][ j] = nm1[y];
j++;
}
else
{
nm2[i][ j] = '\0';
i++;
j = 0;
}
}
printf("\n\n\n\t\t WORD \t LENGTH OF WORD \n\t\t________________________");
for ( c = 0; c < i; c++ )
{
printf("\n\n\n\t\t %s \t\t %d", nm2[c], strlen (nm2[c]) );
}
getch ( );
}
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