Pointer003

Input two numbers and swap them.

#include<stdio.h>
#include<conio.h>
void swap ( int*, int* );
void main ( )
{                  
        int      m, n;
        clrscr ( );
                                     
        printf("\n\n\n\t\t   Enter 1st number..:"); scanf("%d",&m);
        printf("\n\t\t   Enter 2nd number..:"); scanf("%d",&n);
                                
        swap ( &m, &n );
        printf("\n\n\n\n\t\t -- Values after swapping --");
        printf("\n\n\t\t      First value   = %d",m);
        printf("\n\t\t      Second value = %d",n);
        getch ( );
}                           
                   
void swap ( int     *p, int     *q )
{                 
        int     t;
        t = *p;
        *p = *q;
        *q = t;
}

Click here to contact us

Pointer002

Input some numbers in an array. Print the array using pointer.

#include <stdio.h>
#include <conio.h>
void print ( int    arr[], int    l)
{                         
        int i;
        for ( i = 0; i < l; i++ )
        {                             
                 printf("%d, ",*(arr+i));
        }
}
                                                      
void main ( )
{                       
        int    arr[10], i;
        clrscr ( );
        for ( i = 0; i < 10; i++ )
        {                                       
                 printf("\n\t\t\t Enter a number..:");    scanf("%d",&arr[i]);
        }
        printf("\n\n\t The array is..:");
        print ( arr, 10 );
        getch ( );
}

Click here to contact us

Pointer001

Concept of pointer.

#include <stdio.h>
#include <conio.h>
void main ( )
{           
        int       n, *p;
        p = &n;
        n = 5;
        clrscr ( );
                       
        printf("\n\n\n\t\t Number is %d Stored at Address %u", n, &n );
        printf("\n\n\t\t Number is %d Stored at Address %u", *p, p );
        printf("\n\n\t\t Address is %u Stored at Address %u", p, &p );
                       
        getch ( );
}

Click here to contact us

Function041

Write a function to accept two strings as arguments. The function should return the index of the second string in the first string, if it exists and -1 otherwise. Don't use any library routines related to strings.

#include <stdio.h>
#include <conio.h>
void main ( )
{        
        char        str[80], substr[80];
        int           f;
        clrscr ( );
       
        printf("\n\n\n\t Enter the 1st string..:"); gets(str);
        printf("\n\t Enter the substring to search..:");
        gets ( substr );
        f = search ( str, substr );
        if ( f == -1 )
        {                                  
                 printf("\n\n\n\t String not found.");
        }                    
        else                         
        {                    
                 printf("\n\n\n\t String found in position %d",f);
        }
        getch ( );
}                         
                                   
int search ( char    str1[], char    str2[] )
{
        int     i = 0, f;
        for ( i = 0; str1[i] != '\0'; i++ )
        {                                     
                  if ( found ( str1, str2, i ) )
                                return i;
        }
        return -1;
}                     
                                          
int found ( char    str1[], char      str2[], int    i )
{                        
        int      j;
        for ( j = 0; str2[j] != '\0'; i++, j++ )
        {                                                
                  if ( str1[i] != str2 [ j] )
                             return 0;
        }
        return 1;
}

Click here to contact us

Function040

Write a menu driven 'C' program , which prints the options 1,2,3 (as given below) and asks the user to select an option. If user options :
                   1  then find the factors of the entered number
                   2  then check whether the entered number is prime number or not
                   3  then directly exit from the program
The menu should be displayed by a function.

#include <stdio.h>
#include <conio.h>
#include <process.h>
void factor ( int    n )
{         
        int       i;
        printf("\n\t\t The factors are..:");
        for ( i = 1; i <= n; i++ )
        {                                
                  if ( n % i == 0 )
                  {                                            
                                printf("%d, ",i);
                  }                                         
        }                                      
}                                
                             
int prime ( int    n )
{                       
        int      i;
        for ( i = 2; i < n; i++ )
        {                                 
                  if ( n % i == 0 )
                                return 0;
        }
        return 1;
}                              

void menu ( )
{                 
        printf("\n\n\t\t*********************************************\n\n");
        printf("\n\t\t PRESS 1 TO FIND FACTORS\n");
        printf("\n\t\t PRESS 2 TO CHECK IF THE NUMBER IS PRIME\n");
        printf("\n\t\t PRESS 3 TO EXIT\n");
        printf("\n\n\t\t*********************************************\n\n");
}                              
                     
void main ( )
{            
        int      n, ch;
        clrscr ( );
        while ( 1 )
        {                           
               clrscr ( );
               menu ( );
               printf("\n\t\t Enter your choice..:"); scanf("%d",&ch);
               switch ( ch )
               {                                
                      case 1:
                                  printf("\n\t\t Enter a number..:"); scanf("%d",&n);
                                  factor ( n );
                                  break;
                      case 2: 
                                  printf("\n\t\t Enter a number..:"); scanf("%d",&n);
                                  if ( prime ( n ) )
                                             printf("\n\t\t The number is prime.");
                                  else                        
                                             printf("\n\t\t The number is not prime.");
                                  break;
                      case 3:       
                                  exit ( 0 );
                      default: 
                                  printf("\n Please enter a correct choice.");
               }
               getch ( );
        }
}

Click here to contact us

Function039

Write a C program that will enter a line of text, store in an array and then display backwards. The length of the line should be undefined, (being terminated by ENTER key), but less than 80 characters. 

#include <stdio.h>
#include <conio.h>
void backward ( char    str[] )
{              
        int    i;
        for ( i = 0; str[i] != '\0'; i++ );
        printf("\n\n\t The text in backward direction is..:");
        for ( i = i -1; i >= 0; i-- )
        {                   
                    printf("%c",str[i] );
        }
}                          
                
void main ( )
{                     
        char      str[80];
        clrscr ( );
        printf("\n\n\n\t Enter the line of text..:"); gets( str );
        backward ( str );
        getch ( );
}

Click here to contact us

Function038

Write a C program to accept a date in the format DD / MM / YYYY and add an integer to get the resultant date.

#include <stdio.h>
#include <conio.h>

int leap ( int    yy )
{        
     if ( yy % 400 == 0 || ( yy % 100 != 0 && yy % 4 == 0 ) )
                   return 1;
     return 0;
}         
                
void add_day ( int    dd, int    mm, int    yy, int    day )
{             
     int    days[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
     dd = dd + day;
     if ( leap ( yy ) )
               days[2] = 29;
     else                  
               days[2]=28;
     while ( dd > days[mm] )
     {                               
               if ( dd > days[mm] )
               {                           
                         dd = dd - days[mm];
                         mm++;
               }                       
               if ( mm > 12 )
               {                                                
                         mm = 1;
                         yy = yy + 1;
                         if ( leap ( yy ) )
                                    days[2] = 29;
                         else               
                                    days[2]=28;
               }
     }
     printf("\n\n\n\t The resultant date is..:%d/%d/%d",dd,mm,yy);
}                     
                   
void main ( )
{
      int         dd, mm, yy, day;
      clrscr ( );
           
      printf("\n\n\n\t Enter the date in (DD/MM/YYYY) format:");
      scanf("%d/%d/%d",&dd,&mm,&yy);
      printf("\n\t Enter the number of days you want to add..:"); scanf("%d",&day);
      add_day ( dd, mm, yy, day );
      getch ( );
}

Click here to contact us 

Function037

The sequence of Fibonacci numbers is defined as below: f(i)=f(i-1)+f(i-2) with f(0)=1 and f(1)=1. Develop a C program to calculate and display Fibonacci numbers. 

#include <stdio.h>
#include <conio.h>
void main ( )
{                      
        int     n, i, t;
        clrscr ( );
               
        printf("\n\n\n Enter the number of terms of the fibonacci series..:"); scanf("%d",&n);
        printf("\n\n\n OUTPUT....: ");
        for ( i = 0; i < n; i++ )
        {                                
                  t = fibo ( i );
                  printf("%d, ",t);
        }
        getch ( );
}               
                            
int fibo ( int     n )
{                           
        if ( n == 0 || n == 1 )
        {                                
                   return 1;
        }
        return fibo ( n - 1 ) + fibo ( n - 2 );
}

Click here to contact us

Function036

Write a 'C' function to arrange the elements of an integer array in such a way that all the negative elements are before the positive elements. The array is passed to it as an argument.

#include <stdio.h>
#include <conio.h>
void posneg (int    arr[], int    l );
void main ( )
{                  
        int     arr[10], i;
        clrscr ( );
         
        for ( i = 0; i < 10; i++ )
        {                          
                 printf("\n\t\t Enter a number..:"); scanf("%d",&arr[i]);
        }
        printf("\n\n\n\t The array is..: ");
        for ( i = 0; i < 10; i++ )
        {                           
                  printf("%d ",arr[i]);
        }
        posneg ( arr, 10 );
        printf("\n\n\n\t The resultant array is..: ");
        for ( i = 0; i < 10; i++ )
        {                                   
                 printf("%d ",arr[i]);
        }
        getch ( );
}                 
                    
void posneg ( int     arr[], int    l )
{                            
        int     brr[10], j = 0, i;
        for ( i = 0; i < l; i++ )
        {                                  
                 if ( arr[i] < 0 )
                              brr[j++]=arr[i];
        }
        for ( i = 0; i < l; i++ )
        {                                  
                 if ( arr[i] >= 0 )
                              brr[j++]=arr[i];
        }
        for ( i = 0; i < l; i++ )
        {                                      
                 arr[i]=brr[i];
        }
}

Click here to contact us

Function035

Write a 'C' program to compute the following series: 1 - x + x ^ 2 / 2 - x ^ 3 / 6 + x ^ 4 / 24 + ..... + ( - 1 ) ^ nx ^ n / n ! where n and x is to be accepted by the user.

#include <stdio.h>
#include <conio.h>
#include <math.h>
float series ( int    n, float    x )
{                             
        int         i, sf = 1;
        float      s = 0, t;
        for ( i = 0; i <= n; i++ )
        {                                   
                 t = pow ( x, 2 ) / fact ( i );
                 s = s + sf * t;
                 sf = - sf;
        }
        return s;
}
                                    
int fact ( int    n )
{                                   
        int      f = 1;
        while ( n >= 1 )
        {                               
                  f = f * n;
                  n--;
        }
        return f;
}                            
                    
void main ( )
{                            
        int         n;
        float      f, x;
        clrscr ( );
                                  
        printf("\n\n\n\t\t Enter the value of n ( less than 8 )..:"); scanf("%d",&n);
        printf("\n\n\t\t Enter the value of x ..:"); scanf("%f",&x);
        f = series ( n, x );
        printf("\n\n\n\t\t Value = %f",f);
        getch ( );
}

Click here to contact us

Function034

Write a C program to calculate the frequencies of different alphabets, present in a given string. The string of alphabets is to be taken as input from the keyboard.

#include<stdio.h>
#include<conio.h>
int frequency ( char    str[], int    j );
void main ( )
{                      
        char       str[70];
        int          i, freq, j;
        clrscr ( );
                       
        printf("\n\n\n\t Enter a string of alphabets..:");  gets(str);
        for ( j = 'a'; j <= 'z'; j++ )
        {                            
                  freq = frequency ( str, j );
                  if ( freq != 0 )
                  {
                             printf("\n\n\t\t\t Frequency of %c = %d",j,freq);
                  }                      
                  freq = frequency ( str, j - 32 );
                  if ( freq != 0 )
                  {                   
                             printf("\n\n\t\t\t Frequency of %c = %d",j-32,freq);
                  }
        }
        getch();
}

int frequency ( char    str[], int    j )
{                                
        int      freq = 0, i;
        for ( i = 0; str[i] != '\0'; i++ )
        {                                
                  if ( str[i] == j )
                  {                     
                               freq++;
                  }
        }
        return freq;
}

Click here to contact us

Function033

Write a C function print_upper ( ) to prints its character argument in uppercase.

#include <stdio.h>
#include <conio.h>
void print_upper ( char    str[] )
{                  
        int     i;
        for ( i = 0; str[i] != '\0'; i++ )
        {                                      
                  if ( str[i] >= 'a' && str[i] <= 'z' )
                  {                                 
                               str[i] = str[i] - 32;
                  }
        }
}

void main ( )
{                            
        char       str[40];
        clrscr ( );
                           
        printf("\n\n\n\t\t Enter a string..: "); gets(str);
        print_upper ( str );
        printf("\n\n\t\t The upper case string is..: %s",str);
        getch ( );
}

Click here to contact us

Function032

Write a C function wordcount ( ) to count the number of words in a given string and then call in main ( ).

#include <stdio.h>
#include <conio.h>
int wordcount  (char     str[] )
{            
          int     i, w = 1;
          for ( i = 0; str[i] != '\0'; i++ )
          {                                      
                      if ( str[i] == ' ' )
                      {                             
                                  w++;
                      }
          }
          return w;
}                         
                        
void main ( )
{           
        char         str[40];
        int            w = 0;
        clrscr ( );
                           
        printf("\n\n\n\t\t Enter a string..:"); gets(str);
        w = wordcount ( str );
        printf("\n\n\t\t Number of words = %d",w);
        getch ( );
}

Click here to contact us

Function031

Input some elements in increasing order and write a function to search an element using binary search method.

#include <stdio.h>
#include <conio.h>
void main ( )
{                     
        int        arr[10], i, n, p;
        clrscr ( );
        printf("\n\n\n\t\t Input Elements in Increasing Order.\n\n\n");
                  
        for ( i = 0; i < 10; i++ )
        {                         
                  printf("\n\t Enter a number for position [%d] :",i); scanf("%d",&arr[i]);
                  if ( i != 0 && arr[i] < arr[i-1] )
                  {                      
                           printf("\n\t PLEASE ENTER ELEMENTS IN INCREASING ORDER.");
                           i--;
                  }
        }
        clrscr ( );
        printf("\n\n\n\t The array is..:");
        for ( i = 0; i < 10; i++ )
        {                                
                    printf("%d ",arr[i]);
        }               
        printf("\n\n\t Enter an element to search..:"); scanf("%d",&n);
        p = binsearch ( arr, n, 10 );
        if ( p == -1 )
        {                        
                    printf("\n\t Element not found.");
        }                
        else             
        {                
                    printf("\n\t Element found in position %d",p);
        }                        
        getch ( );
}                                
                                       
int binsearch ( int     arr[], int     n, int    len )
{
        int        m, l = 0, u = len - 1;
        while ( u >= l )
        {                          
                 m = ( l + u ) / 2;
                 if ( arr[m] == n )
                 {                                 
                                return m;
                 }
                 if ( arr[m] < n )
                 {                             
                                l = m + 1;
                 }                          
                 else                 
                 {       
                                u = m - 1;
                 }
        }
        return -1;
}

Click here to contact us

Function030

Write a program to find a^n, where a and n can be any positive integer.Define a recursive function power ( ) to perform the operation. 

#include <stdio.h>
#include <conio.h>
int power ( int    a, int    n );
int power ( int    a, int    n )
{                 
       static int     p=1;
       if ( n == 0 )
                 return p;
       p = power ( a, n - 1 ) * a;
}                  
                  
void main ( )
{                      
        int      a, p = 1, n;
        clrscr ( );
                          
        printf("\n\n\n\t\t Enter the number..:"); scanf("%d",&a);
        printf("\n\t\t Enter the power...:"); scanf("%d",&n);
                   
        p = power ( a, n );
        printf("\n\n\t\t %d ^ %d = %d",a,n,p);
        getch ( );
}

Click here to contact us

Case structure006

Write a program to convert an input number in Binary, Octal and Hexadecimal number. The choice should be input by user.

#include <stdio.h>
#include <conio.h>
void main ( )
{            
        int          no, cho, md[50], c, i;
        clrscr ( );
                  
        while ( 1 )
        {                 
               printf ("\n\t\t\t\t MENU");
               printf ("\n\t\t\t\t ====");
               printf ("\n\n\t\t   1. CONVERT FROM DECIMAL TO BINARY\n");
               printf ("\t\t   2. CONVERT FROM DECIMAL TO OCTAL \n");
               printf ("\t\t   3. CONVERT FROM DECIMAL TO HEXADECIMAL \n");
               printf ("\t\t   4. EXIT \n");
               
               printf ("\n\n\n\t\t   Your Choice ? "); scanf ("%d", &cho);
                           
               switch ( cho )
               {             
                     case 1:
                                 printf ("\n\n\t\t Enter a decimal number.......:"); scanf ("%d",&no);
                                 c = 0;
                                 while ( no > 0 )
                                 {            
                                          md[c] = no % 2;
                                          no = no / 2;
                                          c++;
                                 }
                                 printf ("\n\t\t BINARY NUMBER = ");
                                 for ( i = c - 1; i >= 0; i-- )
                                 {                     
                                          printf ("%d", md[i] );
                                 }
                                 break;
                          
                     case 2:       
                                 printf ("\n\n\t\t Enter the number.......:"); scanf ("%d",&no);
                                 c = 0;
                                 while ( no > 0 )
                                 {
                                          md[c] = no % 8;
                                          no = no / 8;
                                          c++;
                                 }
                                 printf ("\n\t\t OCTAL NUMBER = ");
                                 for ( i = c - 1; i >= 0; i-- )
                                 {              
                                          printf ("%d", md[i] );
                                 }
                                 break;
                    
                     case 3:      
                                 printf ("\n\n\t\t Enter the number.......:"); scanf ("%d",&no);
                                 c = 0;
                                 while ( no > 0 )
                                 {                    
                                          md[c] = no % 16;
                                          no = no / 16;
                                          c++;
                                 }
                                 printf ("\n\t\t HEXADECIMAL NUMBER = ");
                                 for ( i = c - 1; i >= 0; i-- )
                                 {            
                                          if ( md[i] > 9 )
                                          {                       
                                                      printf ("%c", md[i] + 55 );
                                          }
                                          else
                                          {
                                                      printf ("%d", md[i] );
                                          }
                                 }
                                 break;
                    
                     case 4:
                                 exit ( );
                                              
                     default:
                                 printf("\n WRONG CHOICE.");
              }
              getch ( );
              clrscr ( );
       }

}

Click here to contact us

Array043

Write a 'C' program to find the minimum of the eight floating point numbers and its place in the array.

#include <stdio.h>
#include <conio.h>
void main ( )
{                   
        float     arr[8], min;
        int        i, pos;
        clrscr ( );
                       
        for ( i = 0; i < 8; i++ )
        {                              
                    printf("\n\t\t Enter a number..:");    scanf("%f",&arr[i]);
        }
        min = arr[0];
        pos = 0;
        for ( i = 1; i < 8; i++ )
        {                           
                    if ( arr[i] < min )
                    {                                
                                 min =arr[i];
                                 pos = i;
                    }
        }
        printf("\n\n\n\t The minimum number is %f and it is in the %d index of the array.",min,pos);
        getch ( );
}

Click here to contact us

Function029

Develop a function to calculate sum of n even integers starting from a given even integer.

#include <stdio.h>
#include <conio.h>
void main ( )
{                        
        int     s, n, t;
        clrscr ( );
      
        do
        {                          
                    printf("\n\n\n\t Enter an even integer to start with..:"); scanf("%d",&s);
        }while ( s % 2 != 0 );
                  
        printf("\n\t Enter the number of even integers..:"); scanf("%d",&n);
        t = sumeven ( s, n );
        printf("\n\n\n\t Starting from %d sum of %d even integers = %d",s,n,t);
        getch ( );
}              
                      
int sumeven ( int    s, int    n )
{                           
        int     i, t = 0;
        for ( i = 1; i <= n; i++, s = s+2 )
        {                                     
                    t = t + s;
        }
        return t;
}

Click here to contact us

Function028

Write a program using function to read an array from the user and print the odd number at odd position and prints the even numbers at even positions. The number of odd numbers and even numbers should be equal.

#include <stdio.h>
#include <conio.h>
void oddeven (int    arr[], int    l );
void main ( )
{                     
        int     arr[10], i;
        clrscr ( );
                                
        for ( i = 0; i < 10; i++ )
        {                      
                    printf("\n\t\t Enter a number..:");    scanf("%d",&arr[i]);
        }                       
        oddeven ( arr, 10 );
        getch ( );
}                       
                                             
void oddeven ( int    arr[], int     l )
{                                  
        int       i, brr[10], j = 0;
                                                   
        printf("\n\n\n\t\t The array is..:\n");
        printf("\n\t POSITION:");
        for ( i = 0; i < l; i++ )
        {                                    
                    printf("%d ",i);
        }                                      
        printf("\n\t ELEMENTS:");
        for ( i = 0; i < l; i++ )
        {                                    
                    printf("%d ",arr[i]);
        }
        for ( i = 0; i < l; i++ )
        {                                      
                    if ( arr[i] % 2 == 0 )
                    {                                     
                                 brr[j] = arr [i];
                                 j = j + 2;
                    }
        }
        j = 1;
        for ( i = 0; i < l; i++ )
        {                                      
                    if ( arr [i] % 2 != 0 )
                    {                                        
                                 brr[j]=arr[i];
                                 j = j + 2;
                    }
        }             
        for ( i = 0; i < l; i++ )
        {                                
                     arr[i]=brr[i];
        }
        printf("\n\n\n\t\t The resultant array is..:\n");
        printf("\n\t POSITION:");
        for ( i = 0; i < l; i++ )
        {                                
                     printf("%d ",i);
        }
        printf("\n\t ELEMENTS:");
             
        for( i = 0; i < l; i++ )
        {                                    
                    printf("%d ",arr[i]);
        }
}

Click here to contact us